The Georgia Milestones Algebra 1 End-of-Course (EOC) assessment is a significant academic milestone. It’s the first high-stakes end-of-course test most Georgia students encounter, it covers an entire year of Algebra 1 content, and — for students in certain grade levels — it carries weight in their final course grade. Understanding the structure and content of the test before walking into it is the difference between an organized, confident approach and an uncertain one.
This guide covers every major Algebra 1 EOC content area with original practice problems, worked solutions, and a realistic study plan.
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Georgia Milestones Algebra 1 EOC: Content Areas
The Algebra 1 EOC assesses Georgia Standards of Excellence (GSE) across these domains:
- Relationships Between Quantities: Interpreting units, dimensional analysis, interpreting expressions in context
- Reasoning with Equations and Inequalities: Solving and interpreting linear equations and inequalities; literal equations; systems of linear equations and inequalities
- Linear and Exponential Relationships: Linear functions (slope, intercepts, transformations); exponential functions (growth/decay, comparing linear vs. exponential); sequences (arithmetic and geometric)
- Descriptive Statistics: Interpreting data displays; measures of center and spread; two-variable data and scatter plots; linear regression
- Expressions and Equations: Polynomial operations; factoring; solving quadratic equations (introduced at end of course)
Practice Problems: Linear Equations and Inequalities
1. Solve: 3(2x − 4) = 5x + 2
6x − 12 = 5x + 2 → x = 14.
2. Solve for t: d = rt
t = d/r. Literal equations test the ability to isolate a specific variable.
3. A plumber charges $80 for a service call plus $60 per hour. A second plumber charges $50 for a service call plus $75 per hour. After how many hours do they charge the same amount?
80 + 60h = 50 + 75h → 30 = 15h → h = 2 hours.
4. Solve and graph: 2x − 5 > 9
2x > 14 → x > 7. Open circle at 7, shaded to the right.
5. Solve: |2x + 3| ≤ 11
−11 ≤ 2x + 3 ≤ 11 → −14 ≤ 2x ≤ 8 → −7 ≤ x ≤ 4.
Practice Problems: Systems of Equations and Inequalities
6. Solve by substitution: y = 3x − 2 and 2x + y = 13
Substitute: 2x + 3x − 2 = 13 → 5x = 15 → x = 3. y = 3(3) − 2 = 7. Solution: (3, 7).
7. Solve by elimination: 4x − y = 11 and 2x + 3y = 7
Multiply first equation by 3: 12x − 3y = 33. Add to second: 14x = 40 → x = 20/7. Substitute back to find y. (If exact values are required: y = 4(20/7) − 11 = 80/7 − 77/7 = 3/7.)
8. A sports store sells footballs for $24 and basketballs for $36. Last week they sold 50 balls for total revenue of $1,560. How many of each type were sold?
Let f = footballs, b = basketballs. f + b = 50 and 24f + 36b = 1,560. From the first: f = 50 − b. Substitute: 24(50 − b) + 36b = 1,560 → 1,200 − 24b + 36b = 1,560 → 12b = 360 → b = 30. f = 20.
Practice Problems: Functions and Slope
9. A line passes through (−3, 1) and (5, 9). Find the slope and write the equation in slope-intercept form.
Slope = (9−1)/(5−(−3)) = 8/8 = 1. Using point (−3, 1): 1 = 1(−3) + b → b = 4. Equation: y = x + 4.
10. Does the table represent a function? x: 1, 2, 3, 3 / y: 5, 8, 11, 14
No. The input x = 3 maps to two different outputs (11 and 14), violating the definition of a function.
11. Write the equation of a line parallel to y = −2x + 5 that passes through (1, 3).
Parallel lines have the same slope. Slope = −2. y − 3 = −2(x − 1) → y = −2x + 5. (In this case, the line is actually the same line — parallel and passing through the same point means coincident. Better example: through (2, 3): y − 3 = −2(x − 2) → y = −2x + 7.)
12. Write an equation perpendicular to y = (3/4)x − 2 passing through (0, 5).
Perpendicular slope = −4/3 (negative reciprocal). y-intercept = 5. Equation: y = −(4/3)x + 5.
Practice Problems: Exponential Functions and Sequences
13. A population of 400 bacteria doubles every 3 hours. Write a function to model this growth. How many bacteria are there after 9 hours?
P(t) = 400 · 2^(t/3), where t is in hours. At t = 9: P = 400 · 2³ = 400 · 8 = 3,200 bacteria.
14. An exponential function satisfies f(0) = 5 and f(1) = 15. Write the function.
f(x) = 5 · 3ˣ. At x = 0: 5 · 1 = 5. At x = 1: 5 · 3 = 15. ✓
15. An arithmetic sequence starts at 8 and increases by 7 each term. Write an explicit formula and find the 20th term.
aₙ = 8 + 7(n − 1) = 7n + 1. a₂₀ = 7(20) + 1 = 141.
16. A geometric sequence starts at 3 and has a common ratio of 4. Write the explicit formula and find the 5th term.
aₙ = 3 · 4^(n−1). a₅ = 3 · 4⁴ = 3 · 256 = 768.
17. A car depreciates in value by 12% each year. It is currently worth $20,000. Write a function and find its value after 5 years.
V(t) = 20,000 · (0.88)^t. V(5) = 20,000 · (0.88)⁵ ≈ 20,000 · 0.5277 ≈ $10,554.
Practice Problems: Statistics
18. The ages of 8 students are: 13, 14, 14, 15, 15, 15, 16, 20. Which measure of center — mean or median — is more appropriate, and why?
The 20 is an outlier. Mean = (13+14+14+15+15+15+16+20)/8 = 122/8 = 15.25. Median = average of 4th and 5th = (15+15)/2 = 15. The median is more appropriate because the outlier (20) pulls the mean up.
19. A scatter plot shows hours studied (x) and test scores (y). The data follows a linear trend. The line of best fit is y = 6.5x + 45. What score would you predict for a student who studies 8 hours?
y = 6.5(8) + 45 = 52 + 45 = 97.
20. Two data sets have the same mean of 50. Set A has a standard deviation of 3; Set B has a standard deviation of 12. What does this tell you about the data?
Set B is much more spread out — the data points are farther from the mean on average. Set A’s values cluster closely around 50, while Set B’s values are widely scattered.
Common Georgia Algebra 1 EOC Mistakes
- Incorrect distribution with negatives in literal equations: Solving for a variable inside parentheses with a negative coefficient requires careful distribution. Many students skip the negative sign on the constant term.
- Confusing arithmetic and geometric sequences: Arithmetic sequences add a constant difference; geometric sequences multiply by a constant ratio. Reading the problem carefully to identify which type is present is the first step.
- Treating exponential growth/decay problems as linear: When a quantity grows or decays by a percentage, the model is y = a(1 ± r)^t — not y = a + bt. Watch for keywords like “doubles,” “triples,” “decreases by 15% per year.”
- Writing wrong form of the line: Some questions ask for slope-intercept form; others ask for point-slope form or standard form. Check what form is requested before writing the final answer.
- Selecting mean when median is more appropriate: On statistics questions, skewed data or outliers call for the median. Questions that ask “which measure of center best represents the data” are testing this judgment.
3-Week Georgia Algebra 1 EOC Study Plan
Week 1: Equations, Inequalities, and Systems
Spend Days 1–2 solving multi-step linear equations and inequalities, including absolute value and compound inequalities. Days 3–4: work through literal equations and word problem translation. Day 5: practice systems of equations using substitution and elimination, with a focus on word problems that require setting up both equations.
Week 2: Functions, Linear Functions, and Exponential Functions
Days 1–2: function notation, domain and range, and identifying functions from tables, graphs, and mappings. Days 3–4: linear functions — slope, intercepts, forms of equations, parallel and perpendicular lines. Day 5: exponential growth and decay, sequences (arithmetic and geometric), and comparing linear vs. exponential change.
Week 3: Statistics, Polynomials, and Full Practice
Days 1–2: descriptive statistics — measures of center and spread, scatter plots, and linear regression interpretation. Day 3: polynomial operations and factoring. Day 4: 20-question full EOC practice test, timed. Day 5: complete error analysis — write out corrected solutions for every missed problem.
Georgia Algebra 1 EOC Resources
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